Jan 01

Jan 01, 2012
kosmo  See all 776 of my articles
Marilyn vos Savant has the highest reported IQ in the world and writes a weekly column where she answers questions from the great unwashed. Often time, the questions are simple enough that a person with average intelligence could answer them. Sometimes, though, she does bobble one and give an obviously wrong answer. (I guess your editor can’t question your work if you’re the smartest person in the world.)
Let’s take a look at this recent question.
I manage a drugtesting program for an organization with 400 employees. Every three months, a randomnumber generator selects 100 names for testing. Afterward, these names go back into the selection pool. Obviously, the probability of an employee being chosen in one quarter is 25 percent. But what’s the likelihood of being chosen over the course of a year?
Jerry Haskins, Vicksburg, Miss.
Marilyn responds:
The probability remains 25 percent, despite the repeated testing. One might think that as the number of tests grows, the likelihood of being chosen increases, but as long as the size of the pool remains the same, so does the probability. Goes against your intuition, doesn’t it?
Yes, it certainly does go against my intuition. There’s a great reason for this – the answer is wrong.
Is the answer counterintuitive?
Before we actually analyze in any detail, ask yourself if this makes sense. Do you really think a person has a 25% chance of being chosen over the course of a year, regardless of the number of tests? So if the company tests 1 time per year or 700 times per year (arrival, lunch break, and right before you leave every day) John Q. Public on the assembly line has a 25% chance of being picked at any time during the course of a year?
Give Marilyn a point for correctly suggesting that her answer is counterintuitive.
Walk through the 4 tests
OK, let’s walk through the selections in each of the quarters.
 Quarter 1: Of the 400 employees, 100 are selected and 300 are not. At this point, we’ve broken the single group of employees into two subgroups – those who have been selected and those who have not.
 Quarter 2: 100 of the 400 employees are selected again. If the sampling is truly random, 25% of each subgroup will be selected. This means that 25% of the 100 employees (25) who were selected in the 1st quarter will be selected again, and 25% of the 300 employees (75) who were not selected in the 1st quarter will be selected. The “selected at least once” subgroup now grows to 175 while the “never selected” subgroup shrinks to 225. From this point on, we’ll focus on the “never selected” group.
 Quarter 3: The “never selected” group drops to 169.
 Quarter 4: The “never selected” group drops to 127.
At the end of the year, 127 of the 400 employees (31.75%) have completely avoided the testing, while 273 (68.25%) have been selected at least once. 1 or 2 people would have been selected all four times.
Show me the math
As is often the case with probability, the easiest way to attack this is to computer the odds of the opposite circumstance and subtract this from 100%. The odds of being selected one of more times would involve computing the odds of being selected once, twice, three times, or four times and then adding the results.
Alternately, we can easily calculated the odds of never being selected, and just subtract this from 100% to arrive at the likelihood of being selected at least once.
The odds of avoiding testing in any quarter is 75%. Thus, we simple raise .75 to the power of 4 (.75^^{4}) to arrive at the odds of never being selected for testing – .3164, or 31.64%. Thus the odds of being selected at least once is 68.36%. This differs slightly from the result above because the 68.25% involved some rounding (since we must use whole people and not fractions).
The moral of the story?
Don’t place too much trust (or distrust) in the messenger. Pay attention to the actual message.
5 Comments
Assorted
Ask Marilyn
http://www.thesoapboxers.com/askmarilynaboutrandomdrugtesting/
jammen
Jan 02, 2012 @ 19:24:34
My company only has two employees, not 400, and they randomly drug test daily, not quarterly. Now I knew that my odds of being tested today were 50%, so I was overjoyed to learn that at the end of the year I still had a 50% chance of beating it.
Unfortunately I tested positive for marijuana the next day, but in my heart I still believe that I can trust Marilyn.
p.s. The editors must have mangled the answer as that is a kindergarten mistake that no puzzle person could ever make.
Total Comment by jammen: 1
kosmo
Jan 02, 2012 @ 22:17:32
Very nice, Jammen. You made the point even more clear.
I have seen Marilyn have problems with issues related to probability of independent events before, so it wouldn’t shock me if the error was hers. But, yes, it’s an elementary error that shouldn’t have slipped through the cracks, regardless of who made the error.
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kosmo
Jan 22, 2012 @ 14:28:16
OK, I’ll give some credit to Marilyn. In today’s column, she openly admits that she gave the wrong answer to this question.
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Nov 06, 2018 @ 13:37:17
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Edwin K. Haefner
Nov 07, 2018 @ 12:40:39
Hi,
I have seen Marilyn have issues with problems associated with the likelihood of freelance events before, therefore it wouldn’t shock Pine Tree State if the error was hers. But, yes, it’s AN elementary error that shouldn’t have slipped through the cracks, despite WHO created the error.
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Total Comments by Edwin K. Haefner: 2